The roots of the given equation (p−q)x2+(q−r)x+(r−p)=0 are :p−qr−p,1q−rp−q,1r−pp−q,1None of these
Question
The roots of the given equation (p−q)x2+(q−r)x+(r−p)=0 are :p−qr−p,1q−rp−q,1r−pp−q,1None of these
Solution
The roots of the quadratic equation ax^2 + bx + c = 0 can be found using the formula x = [-b ± sqrt(b^2 - 4ac)] / (2a).
In the given equation (p−q)x^2 + (q−r)x + (r−p) = 0, we can identify a = p - q, b = q - r, and c = r - p.
Substituting these values into the quadratic formula gives us:
x = [-(q - r) ± sqrt((q - r)^2 - 4*(p - q)(r - p))] / 2(p - q)
Solving this equation will give us the roots of the given equation. However, the options provided do not match the solution to this equation, so the correct answer is "None of these".
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