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The main ore of manganese, pyrolusite, is mainly MnO2. A solution of SnCl2 can be used to estimate the percentage of MnO2 in a sample of pyrolusite, using the following method.*             A known mass of pyrolusite is warmed with an acidified solution containing a known amount of SnCl2.*             The excess Sn2+(aq) ions are titrated with a standard solution of KMnO4.In one such experiment, 0.100g of pyrolusite was warmed with an acidified solution containing 2.00 x 10-3 mol Sn2+. After the reaction was complete, the mixture was titrated with 0.0200 mol dm-3 KMnO4, and required 18.1 cm3 of this solution to reach end point.Balance the following half equations and give balanced overall equationsMnO4-   →           Mn2+                                      and                        MnO2    →           Mn2+Sn2+        →           Sn4+                                                                    Sn2+        →           Sn4+ and use them, and the information above to calculate the percentage of MnO2 in pyrolusite. The percentage is?

Question

The main ore of manganese, pyrolusite, is mainly MnO2. A solution of SnCl2 can be used to estimate the percentage of MnO2 in a sample of pyrolusite, using the following method.*             A known mass of pyrolusite is warmed with an acidified solution containing a known amount of SnCl2.*             The excess Sn2+(aq) ions are titrated with a standard solution of KMnO4.In one such experiment, 0.100g of pyrolusite was warmed with an acidified solution containing 2.00 x 10-3 mol Sn2+. After the reaction was complete, the mixture was titrated with 0.0200 mol dm-3 KMnO4, and required 18.1 cm3 of this solution to reach end point.Balance the following half equations and give balanced overall equationsMnO4-   →           Mn2+                                      and                        MnO2    →           Mn2+Sn2+        →           Sn4+                                                                    Sn2+        →           Sn4+ and use them, and the information above to calculate the percentage of MnO2 in pyrolusite. The percentage is?

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Solution

First, let's balance the half equations:

  1. MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
  2. MnO2 + 4H+ + 2e- → Mn2+ + 2H2O
  3. Sn2+ → Sn4+ + 2e-
  4. Sn2+ → Sn4+ + 2e-

The overall equations are:

  1. MnO4- + 8H+ + 5Sn2+ → Mn2+ + 4H2O + 5Sn4+
  2. MnO2 + 4H+ + 2Sn2+ → Mn2+ + 2H2O + 2Sn4+

Now, let's calculate the percentage of MnO2 in pyrolusite.

From the titration, we know that 18.1 cm3 of 0.0200 mol dm-3 KMnO4 was used. This means that 18.1 cm3 * 0.0200 mol dm-3 = 3.62 x 10-4 mol of KMnO4 was used.

From the balanced equation, we know that 1 mol of KMnO4 reacts with 1 mol of MnO2. Therefore, 3.62 x 10-4 mol of KMnO4 reacts with 3.62 x 10-4 mol of MnO2.

The molar mass of MnO2 is 54.94 g/mol (Mn) + 2*16.00 g/mol (O) = 86.94 g/mol.

Therefore, the mass of MnO2 in the sample is 3.62 x 10-4 mol * 86.94 g/mol = 0.0315 g.

The percentage of MnO2 in the sample is (0.0315 g / 0.100 g) * 100% = 31.5%.

This problem has been solved

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