Write the equilibrium constant expression for this reaction:2H+(aq)+C2O2−4(aq) → H2C2O4(aq)
Question
Write the equilibrium constant expression for this reaction:2H+(aq)+C2O2−4(aq) → H2C2O4(aq)
Solution 1
The equilibrium constant expression for the reaction 2H+(aq) + C2O2−4(aq) → H2C2O4(aq) is written as:
Kc = [H2C2O4] / ([H+]^2 * [C2O2−4])
Where:
- Kc is the equilibrium constant
- [H2C2O4], [H+], and [C2O2−4] are the molar concentrations of H2C2O4, H+, and C2O2−4 at equilibrium, respectively.
- The exponents on the concentrations in the expression are equal to the stoichiometric coefficients in the balanced chemical equation.
Solution 2
The equilibrium constant expression for the given reaction is written as the ratio of the concentrations of the products to the concentrations of the reactants, each raised to the power of their stoichiometric coefficients in the balanced chemical equation.
For the reaction: 2H+(aq) + C2O4^2-(aq) → H2C2O4(aq)
The equilibrium constant expression (Kc) would be:
Kc = [H2C2O4] / ([H+]^2 * [C2O4^2-])
Where:
- [H2C2O4] is the molar concentration of H2C2O4 at equilibrium
- [H+] is the molar concentration of H+ at equilibrium
- [C2O4^2-] is the molar concentration of C2O4^2- at equilibrium
The concentrations are usually in moles per liter (M). The brackets denote the concentration of the species at equilibrium.
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