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X is four times as efficient as Y in respect of doing a particular work. Working together they complete the work in 16 days. In how many days y working alone will be able to half the work?Question 10Answera.80b.20c.40d.60

Question

X is four times as efficient as Y in respect of doing a particular work. Working together they complete the work in 16 days. In how many days y working alone will be able to half the work?Question 10Answera.80b.20c.40d.60

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Solution

Let's solve this step by step:

Step 1: Let's assume the amount of work to be 1 (for simplicity).

Step 2: If X is four times as efficient as Y, then if Y does 1 unit of work, X does 4 units of work.

Step 3: Working together, X and Y complete the work in 16 days. So, in 1 day, they do 1/16 of the work.

Step 4: In 1 day, X and Y together do 1/16 of the work. Since X does 4 units of work for every 1 unit of work Y does, we can write this as 4x + x = 1/16, where x is the amount of work Y does in one day. Solving for x gives us x = 1/80.

Step 5: So, Y can do 1/80 of the work in 1 day. To do half the work (1/2), Y would need 80 * 2 = 160 days.

So, the answer is not in the options given. Y would need 160 days to do half the work alone.

This problem has been solved

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