In a lucky dip game ten wrapped items are stored in a bin. One item is a rotten egg and has been included as a prank. Jennifer draws an item from the bin. What is her probability of obtaining the rotten egg (round your answer to one decimal place)?
Question
In a lucky dip game ten wrapped items are stored in a bin. One item is a rotten egg and has been included as a prank. Jennifer draws an item from the bin. What is her probability of obtaining the rotten egg (round your answer to one decimal place)?
Solution
To calculate the probability of an event, you divide the number of ways the event can occur by the total number of outcomes.
Step 1: Identify the total number of outcomes. In this case, there are 10 items in the bin.
Step 2: Identify the number of ways the event can occur. In this case, there is only 1 rotten egg.
Step 3: Divide the number of ways the event can occur by the total number of outcomes.
So, the probability of Jennifer drawing the rotten egg is 1/10 = 0.1 or 10% when rounded to one decimal place.
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