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In a lucky dip game ten wrapped items are stored in a bin. One item is a rotten egg and has been included as a prank. Jennifer draws an item from the bin. What is her probability of obtaining the rotten egg (round your answer to one decimal place)?

Question

In a lucky dip game ten wrapped items are stored in a bin. One item is a rotten egg and has been included as a prank. Jennifer draws an item from the bin. What is her probability of obtaining the rotten egg (round your answer to one decimal place)?

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Solution

To calculate the probability of an event, you divide the number of ways the event can occur by the total number of outcomes.

Step 1: Identify the total number of outcomes. In this case, there are 10 items in the bin.

Step 2: Identify the number of ways the event can occur. In this case, there is only 1 rotten egg.

Step 3: Divide the number of ways the event can occur by the total number of outcomes.

So, the probability of Jennifer drawing the rotten egg is 1/10 = 0.1 or 10% when rounded to one decimal place.

This problem has been solved

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