The problem can be solved by using the properties of triangles and the definition of an obtuse triangle. An obtuse triangle is a triangle in which one of the angles is greater than 90 degrees.

Step 1: Draw a square.

Step 2: Draw a diagonal in the square. This will divide the square into two right triangles.

Step 3: In each right triangle, draw a line from the right angle to the hypotenuse. This will divide each right triangle into two triangles, one of which is obtuse.

So, we can divide a square into at least four obtuse triangles.

Question

The problem can be solved by using the properties of triangles and the definition of an obtuse triangle. An obtuse triangle is a triangle in which one of the angles is greater than 90 degrees.

Step 1: Draw a square.

Step 2: Draw a diagonal in the square. This will divide the square into two right triangles.

Step 3: In each right triangle, draw a line from the right angle to the hypotenuse. This will divide each right triangle into two triangles, one of which is obtuse.

So, we can divide a square into at least four obtuse triangles.

Knowee AI · Accepted Answer

The problem can be solved by using the properties of triangles and the definition of an obtuse triangle. An obtuse triangle is a triangle in which one of the angles is greater than 90 degrees.

Step 1: Draw a square.

Step 2: Draw a diagonal in the square. This will divide the square into two right triangles.

Step 3: In each right triangle, draw a line from the right angle to the hypotenuse. This will divide each right triangle into two triangles, one of which is obtuse.

So, we can divide a square into at least four obtuse triangles.

We want to divide a square into obtuse triangles such that every two trianglesmeet at a common vertex or at a common edge or are disjoint. At least howmany triangles can we have?

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