What is the result stored in x, after evaluating the following code snippet?int x =-5;X= X++ %2+3 *--x +2:

The code snippet you provided seems to be written in Java or a similar language. Let's break it down step by step:

1. int x = -5; This line initializes an integer variable x with a value of -5.

2. x = x++ % 2 + 3 * --x + 2; This line is a bit more complex, so let's break it down further:

   • x++ This is a post-increment operation. It means that x is used in its current state (which is -5), and then incremented by 1 after the operation. So, for this operation, x is -5, but immediately after it becomes -4.

   • --x This is a pre-decrement operation. It means that x is decremented by 1 before it's used in the operation. Since x was -4 after the post-increment, it now becomes -5 again before this operation.

   • % This is the modulus operator. It returns the remainder of the division of the number to the left by the number on the right. -5 % 2 equals -1 because -5 divided by 2 equals -2 with a remainder of -1.

   • * This is the multiplication operator. 3 * -5 equals -15.

   • + This is the addition operator. -1 + -15 + 2 equals -14.

So, after evaluating the entire code snippet, x should be -14.