.Rajeev went from Delhi to Chandigarh and returned to Delhi on his motorbike. The odometer of that read 4200 km at the start of trip and 4460 km at the end of his trip. If Rajeev took 4 h 20 min to complete his trip, then find the average velocity in km/h.
Question
.Rajeev went from Delhi to Chandigarh and returned to Delhi on his motorbike. The odometer of that read 4200 km at the start of trip and 4460 km at the end of his trip. If Rajeev took 4 h 20 min to complete his trip, then find the average velocity in km/h.
Solution
To find the average velocity, we need to know the total displacement and the total time.
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Total displacement: Since Rajeev started and ended his trip in Delhi, his total displacement is 0 km. Displacement is a vector quantity that refers to "how far out of place an object is" in a certain direction; it is the object's overall change in position.
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Total time: The problem states that Rajeev took 4 hours and 20 minutes to complete his trip. To convert this to hours, we can convert 20 minutes to hours by dividing by 60 (since there are 60 minutes in an hour). So, 20 minutes is 20/60 = 0.33 hours. Therefore, the total time in hours is 4 + 0.33 = 4.33 hours.
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Average velocity: Velocity is defined as the rate of change of displacement with time. It is a vector quantity with both magnitude and direction. The formula for average velocity is total displacement divided by total time. Since the total displacement is 0 km (Rajeev ended up in the same place he started), the average velocity is also 0 km/h, regardless of the total time.
So, the average velocity of Rajeev's trip is 0 km/h.
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