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A Single phase PFC Circuit is required to be designed for the following Specs:Rated output power Po: 2.5kW AC input voltage range: 100-270VAC Grid frequency range: 50±1Hz d.Output DC voltage  400VSwitch frequency fsw: 120kHz Efficiency h: >94% Therefore: The Max Duty Cycle Value is Select one:a. 0.9b. 0.45c. 0.65d. 0.8

Question

A Single phase PFC Circuit is required to be designed for the following Specs:Rated output power Po: 2.5kW AC input voltage range: 100-270VAC Grid frequency range: 50±1Hz d.Output DC voltage  400VSwitch frequency fsw: 120kHz Efficiency h: >94% Therefore: The Max Duty Cycle Value is Select one:a. 0.9b. 0.45c. 0.65d. 0.8

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Solution

The maximum duty cycle value for a single phase PFC circuit can be calculated using the formula:

Dmax = Vin(min) / Vout

Where: Vin(min) is the minimum input AC voltage Vout is the output DC voltage

Given: Vin(min) = 100V (from the AC input voltage range: 100-270V) Vout = 400V (output DC voltage)

Substituting these values into the formula gives:

Dmax = 100V / 400V = 0.25

However, this value is not listed in the options provided. Therefore, it seems there may be a mistake in the question or the provided options. The calculated maximum duty cycle value is 0.25, not 0.9, 0.45, 0.65, or 0.8.

This problem has been solved

Similar Questions

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