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A Priority-Queue is implemented as a Max-Heap. Initially, it has 5 elements. The level-order traversal of the heap is given below: 10, 8, 5, 3, 2 Two new elements ”1‘ and ”7‘ are inserted in the heap in that order. The level-order traversal of the heap after the insertion of the elements is:10, 8, 7, 5, 3, 2, 110, 8, 7, 5, 3, 1, 510, 8, 7, 5, 2, 1, 510, 8, 7, 3, 2, 3, 5

Question

A Priority-Queue is implemented as a Max-Heap. Initially, it has 5 elements. The level-order traversal of the heap is given below: 10, 8, 5, 3, 2 Two new elements ”1‘ and ”7‘ are inserted in the heap in that order. The level-order traversal of the heap after the insertion of the elements is:10, 8, 7, 5, 3, 2, 110, 8, 7, 5, 3, 1, 510, 8, 7, 5, 2, 1, 510, 8, 7, 3, 2, 3, 5

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Solution

The level-order traversal of the heap after the insertion of the elements "1" and "7" would be: 10, 8, 7, 5, 3, 2, 1.

Here's the step-by-step process:

  1. The initial max-heap is: 10, 8, 5, 3, 2.
  2. We insert "1" into the heap. But since "1" is less than the root (10), it will go to the next available spot in the level order, which is after "2". So now the heap is: 10, 8, 5, 3, 2, 1.
  3. Next, we insert "7" into the heap. "7" is less than the root (10) but greater than its parent "2". So, we swap "7" and "2". Now the heap is: 10, 8, 7, 5, 3, 2, 1.

So, the level-order traversal of the heap after the insertion of the elements "1" and "7" is: 10, 8, 7, 5, 3, 2, 1.

This problem has been solved

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