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Let [(A)\vec] = 3  [^(i)] − 6  [^(j)] and [(B)\vec] = −6  [^(i)] + 2  [^(j)]. What is [(C)\vec] = [(A)\vec] − 4 [(B)\vec]? Give your answer as a magnitude and direciton.Magnitude: Direction (specify as an angle measured counterclockwise from the positive x axis):

Question

Let [(A)\vec] = 3  [^(i)] − 6  [^(j)] and [(B)\vec] = −6  [^(i)] + 2  [^(j)]. What is [(C)\vec] = [(A)\vec] − 4 [(B)\vec]? Give your answer as a magnitude and direciton.Magnitude: Direction (specify as an angle measured counterclockwise from the positive x axis):

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Solution

To find the vector C, we first need to multiply vector B by 4. This gives us:

4[(B)\vec] = 4(-6[^(i)] + 2[^(j)]) = -24[^(i)] + 8[^(j)]

Then we subtract this result from vector A:

[(C)\vec] = [(A)\vec] - 4[(B)\vec] = (3[^(i)] - 6[^(j)]) - (-24[^(i)] + 8[^(j)]) = 27[^(i)] - 14[^(j)]

This is the vector C in component form.

To find the magnitude of vector C, we use the formula for the magnitude of a vector:

|[(C)\vec]| = sqrt((27)^2 + (-14)^2) = sqrt(729 + 196) = sqrt(925) ≈ 30.4

The direction θ of the vector can be found using the formula θ = atan(y/x), where x and y are the i and j components of the vector respectively. In this case, x = 27 and y = -14.

θ = atan(-14/27) ≈ -27.4 degrees

However, because the vector is in the fourth quadrant (since its i component is positive and its j component is negative), we add 360 degrees to this result to get the direction measured counterclockwise from the positive x axis:

θ = -27.4 degrees + 360 degrees = 332.6 degrees

So, the magnitude of vector C is approximately 30.4, and its direction is approximately 332.6 degrees counterclockwise from the positive x axis.

This problem has been solved

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