Evaluate:log, base, 128, one eigthlog 128​ 81​

It seems like there might be a misunderstanding in the question. However, I'll try to interpret it as best as I can.

If you're asking to evaluate the logarithm base 128 of 1/8 and the logarithm base 128 of 81, here's how you can do it:

1. Logarithm base 128 of 1/8:

   log128(1/8) = log128(128^-3) = -3

2. Logarithm base 128 of 81:

   This is a bit more complicated because 81 is not a power of 128. You can use the change of base formula to evaluate this:

   log128(81) = log10(81) / log10(128) ≈ 0.431

So, log128(1/8) = -3 and log128(81) ≈ 0.431.