2! + 4! + 6! + 8! + 10! +………….+100! When divided by 5, will give remainder.2301
Question
2! + 4! + 6! + 8! + 10! +………….+100! When divided by 5, will give remainder.2301
Solution
The given series is a factorial series with an increment of 2.
The factorial of any number greater than or equal to 5 is always divisible by 5. This is because the factorial of a number is the product of all positive integers less than or equal to that number, and for numbers greater than or equal to 5, one of those integers will be 5, making the factorial divisible by 5.
So, from 5! onwards, all terms in the series are divisible by 5.
Therefore, we only need to consider the first two terms to find the remainder when divided by 5.
2! = 2 4! = 24
Adding these gives 2 + 24 = 26
So, when 26 is divided by 5, the remainder is 1.
Therefore, the remainder when the given series is divided by 5 is 1.
Similar Questions
How many trailing zeros will be there in 2302! (factorial of 2302)?
Find the number of zeros at the end of the 120! + 230! + 40! + 450! + 60! + 670!
The remainderwhen 1! + 2! + 3! + …+ 20!15 Select an answerA4B3C5D7
The remainder when 1! + 2! + 3! + …. +100! Is divided by 24 is
What is the remainder when 120! is divided by 12024?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.