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One mole of an ideal monatomic gas is taken through a thermodynamic process shown in the P-V diagram. The heat supplied to the system in this process is K×(180/2+10)P0V0. Determine the value of K.

Question

One mole of an ideal monatomic gas is taken through a thermodynamic process shown in the P-V diagram. The heat supplied to the system in this process is K×(180/2+10)P0V0. Determine the value of K.

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Solution

To determine the value of K, we need to analyze the given expression for the heat supplied to the system in the thermodynamic process. The expression is K×(180/2+10)P0V0.

Let's simplify the expression step by step:

  1. Simplify the expression inside the parentheses: 180/2+10 = 90+10 = 100.

  2. Now we have K×100P0V0.

  3. Since we are given that the gas is an ideal monatomic gas, we can use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

  4. In this case, we are given that we have one mole of the gas, so n = 1.

  5. Rearranging the ideal gas law, we have PV = RT.

  6. Dividing both sides of the equation by V, we get P = (RT)/V.

  7. Substituting this expression for P into our original expression, we have K×100((RT)/V)0V0.

  8. Simplifying further, we have K×100RT.

  9. Now, we know that heat supplied to the system is given by the equation Q = nCΔT, where Q is the heat, n is the number of moles, C is the molar heat capacity, and ΔT is the change in temperature.

  10. In this case, we are given that the heat supplied is K×100RT.

  11. Since we have one mole of the gas, n = 1, and we can rewrite the equation as Q = CΔT.

  12. Comparing this equation with our given expression, we can equate the two: K×100RT = CΔT.

  13. From this equation, we can see that K = CΔT/(100RT).

Therefore, the value of K is CΔT/(100RT).

This problem has been solved

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