The general solution to the differential equation ๐๐ฆ๐๐ฅ=๐ฅ๐ฆ is ๐ฆ=ยฑ๐ฅ2+๐ถ. Let ๐ฆ=๐(๐ฅ) be the particular solution to the differential equation with the initial condition ๐(โ2)=โ2. Which of the following is an expression for ๐(๐ฅ) and the domain for which the solution is valid?
Question
The general solution to the differential equation ๐๐ฆ๐๐ฅ=๐ฅ๐ฆ is ๐ฆ=ยฑ๐ฅ2+๐ถ. Let ๐ฆ=๐(๐ฅ) be the particular solution to the differential equation with the initial condition ๐(โ2)=โ2. Which of the following is an expression for ๐(๐ฅ) and the domain for which the solution is valid?
Solution
The given differential equation is dy/dx = xy. This is a first order linear differential equation. The general solution to this differential equation is given as y = ยฑx^2 + C, where C is the constant of integration.
We are given an initial condition f(-2) = -2. We can use this to find the particular solution.
Substitute x = -2 and y = -2 into the general solution to solve for C:
-2 = -(-2)^2 + C -2 = -4 + C C = -2 + 4 C = 2
So, the particular solution is y = f(x) = ยฑx^2 + 2.
The domain for which the solution is valid is all real numbers, because the function is defined for all x in the set of real numbers. Therefore, the domain is (-โ, โ).
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