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The general solution to the differential equation ๐‘‘๐‘ฆ๐‘‘๐‘ฅ=๐‘ฅ๐‘ฆ is ๐‘ฆ=ยฑ๐‘ฅ2+๐ถ. Let ๐‘ฆ=๐‘“(๐‘ฅ) be the particular solution to the differential equation with the initial condition ๐‘“(โˆ’2)=โˆ’2. Which of the following is an expression for ๐‘“(๐‘ฅ) and the domain for which the solution is valid?

Question

The general solution to the differential equation ๐‘‘๐‘ฆ๐‘‘๐‘ฅ=๐‘ฅ๐‘ฆ is ๐‘ฆ=ยฑ๐‘ฅ2+๐ถ. Let ๐‘ฆ=๐‘“(๐‘ฅ) be the particular solution to the differential equation with the initial condition ๐‘“(โˆ’2)=โˆ’2. Which of the following is an expression for ๐‘“(๐‘ฅ) and the domain for which the solution is valid?

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Solution

The given differential equation is dy/dx = xy. This is a first order linear differential equation. The general solution to this differential equation is given as y = ยฑx^2 + C, where C is the constant of integration.

We are given an initial condition f(-2) = -2. We can use this to find the particular solution.

Substitute x = -2 and y = -2 into the general solution to solve for C:

-2 = -(-2)^2 + C -2 = -4 + C C = -2 + 4 C = 2

So, the particular solution is y = f(x) = ยฑx^2 + 2.

The domain for which the solution is valid is all real numbers, because the function is defined for all x in the set of real numbers. Therefore, the domain is (-โˆž, โˆž).

This problem has been solved

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