The energy dissipated by a wire can be calculated using the formula:

E = V * I * t

where:
E is the energy dissipated,
V is the potential difference,
I is the current, and
t is the time.

Given:
V = 10 mV = 10 * 10^-3 V,
I = 0.10 µA = 0.10 * 10^-6 A, and
t = 10 s,

we can substitute these values into the formula:

E = (10 * 10^-3 V) * (0.10 * 10^-6 A) * (10 s) = 10 * 10^-9 J = 10 nJ.

So, the energy dissipated by the wire in a time of 10 s is 10 nJ. The correct answer is D.

Question

The energy dissipated by a wire can be calculated using the formula:

E = V * I * t

where:
E is the energy dissipated,
V is the potential difference,
I is the current, and
t is the time.

Given:
V = 10 mV = 10 * 10^-3 V,
I = 0.10 µA = 0.10 * 10^-6 A, and
t = 10 s,

we can substitute these values into the formula:

E = (10 * 10^-3 V) * (0.10 * 10^-6 A) * (10 s) = 10 * 10^-9 J = 10 nJ.

So, the energy dissipated by the wire in a time of 10 s is 10 nJ. The correct answer is D.

Knowee AI · Accepted Answer

The energy dissipated by a wire can be calculated using the formula:

E = V * I * t

where:
E is the energy dissipated,
V is the potential difference,
I is the current, and
t is the time.

Given:
V = 10 mV = 10 * 10^-3 V,
I = 0.10 µA = 0.10 * 10^-6 A, and
t = 10 s,

we can substitute these values into the formula:

E = (10 * 10^-3 V) * (0.10 * 10^-6 A) * (10 s) = 10 * 10^-9 J = 10 nJ.

So, the energy dissipated by the wire in a time of 10 s is 10 nJ. The correct answer is D.

A wire carries a current of 0.10 µA. The potential difference across the wire is 10 mV.How much energy is dissipated by the wire in a time of 10 s?A 1.0 pJ B 10 pJ C 1.0 nJ D 10 nJ