The compound interest formula is A = P(1 + r/n)^(nt), where:

A = the amount of money accumulated after n years, including interest.
P = the principal amount (the initial amount of money)
r = annual interest rate (in decimal)
n = number of times that interest is compounded per year
t = the time the money is invested for in years

Given in the problem:
A = ₹ 13,230 (the maturity amount after one year)
r = 10% per annum = 0.10 (in decimal)
n = 2 (since the interest is compounded half-yearly)
t = 1 year

We can substitute these values into the formula and solve for P:

13,230 = P(1 + 0.10/2)^(2*1)
13,230 = P(1 + 0.05)^2
13,230 = P(1.05)^2
13,230 = P * 1.1025

Now, solve for P:

P = 13,230 / 1.1025
P = ₹ 12,000 approximately

So, the sum is ₹ 12,000. Therefore, the answer is 12,000.

Question

The compound interest formula is A = P(1 + r/n)^(nt), where:

A = the amount of money accumulated after n years, including interest.
P = the principal amount (the initial amount of money)
r = annual interest rate (in decimal)
n = number of times that interest is compounded per year 
t = the time the money is invested for in years

Given in the problem:
A = ₹ 13,230 (the maturity amount after one year)
r = 10% per annum = 0.10 (in decimal)
n = 2 (since the interest is compounded half-yearly)
t = 1 year

We can substitute these values into the formula and solve for P:

13,230 = P(1 + 0.10/2)^(2*1)
13,230 = P(1 + 0.05)^2
13,230 = P(1.05)^2
13,230 = P * 1.1025

Now, solve for P:

P = 13,230 / 1.1025
P = ₹ 12,000 approximately

So, the sum is ₹ 12,000. Therefore, the answer is 12,000.

Knowee AI · Accepted Answer

The compound interest formula is A = P(1 + r/n)^(nt), where:

A = the amount of money accumulated after n years, including interest.
P = the principal amount (the initial amount of money)
r = annual interest rate (in decimal)
n = number of times that interest is compounded per year 
t = the time the money is invested for in years

Given in the problem:
A = ₹ 13,230 (the maturity amount after one year)
r = 10% per annum = 0.10 (in decimal)
n = 2 (since the interest is compounded half-yearly)
t = 1 year

We can substitute these values into the formula and solve for P:

13,230 = P(1 + 0.10/2)^(2*1)
13,230 = P(1 + 0.05)^2
13,230 = P(1.05)^2
13,230 = P * 1.1025

Now, solve for P:

P = 13,230 / 1.1025
P = ₹ 12,000 approximately

So, the sum is ₹ 12,000. Therefore, the answer is 12,000.

If the compound interest is compounded half-yearly, then investing a certain sum at the rate of 10% per annum, the maturity amount after one year is ₹ 13,230. What is the sum? 12,50012,00012,750More than one of the aboveNone of the above

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