Knowee
Questions
Features
Study Tools

If a variable is a pointer to a structure, then which of the following operator is used to access data members of the structure through the pointer variable? ans. -> * . &

Question

If a variable is a pointer to a structure, then which of the following operator is used to access data members of the structure through the pointer variable?

ans. ->

.

&

🧐 Not the exact question you are looking for?Go ask a question

Solution

The operator used to access data members of a structure through a pointer variable is the "->" operator.

Here's a step-by-step explanation:

  1. In C and C++, structures are user-defined data types that allow us to store different types of data items together.

  2. If we have a pointer to a structure, we can't directly use the dot (.) operator to access the structure's members, because the dot operator is used when we have an actual instance of the structure.

  3. Instead, we use the arrow (->) operator. The arrow operator is used with a pointer to an object to access the object's members.

  4. For example, if we have a pointer p to a structure s with a member m, we would use p->m to access the member m of the structure pointed to by p.

  5. The "*" operator is used to dereference a pointer, i.e., to get the value that the pointer points to. The "&" operator is used to get the address of a variable. But neither of these operators is used to access members of a structure through a pointer.

This problem has been solved

Similar Questions

How do you access a member of a structure using a structure pointer in C?*1 pointWith the dot operator (.)With the arrow operator (->)With the ampersand (&)With the asterisk (*

Which operator is used to access data members of the outer structure?

The operator used to get value at address stored in a pointer variable isa.*b.&c.&&d.||

Which operator is used to obtain the memory address of a variable in C?

The indirection operator (*) returns the value stored in the address that the operand contains. The expression is itself an lvalue.The indirection and address-of operators are inverses of one another. The result of *&x is x.

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.