To solve this problem, we need to create a function that calculates the number of distinct subsequences for each string and then compares them. Here is a Python solution:

```python
def distinct_subsequences(s):
n = len(s)
dp = [0 for _ in range(n+1)]
last = [-1 for _ in range(256)]
dp[0] = 1
for i in range(1, n+1):
dp[i] = 2*dp[i-1]
if last[ord(s[i-1])] != -1:
dp[i] = dp[i] - dp[last[ord(s[i-1])]]
last[ord(s[i-1])] = i-1
return dp[n]

def betterString(str1, str2):
if distinct_subsequences(str1) = distinct_subsequences(str2):
return str1
else:
return str2
```

The `distinct_subsequences` function calculates the number of distinct subsequences of a string using dynamic programming. The `betterString` function uses this function to compare the number of distinct subsequences of `str1` and `str2` and returns the better string. The time complexity is O(max(str1.length, str2.length)) and the auxiliary space complexity is also O(max(str1.length, str2.length)).

Question

To solve this problem, we need to create a function that calculates the number of distinct subsequences for each string and then compares them. Here is a Python solution:

```python
def distinct_subsequences(s):
    n = len(s)
    dp = [0 for _ in range(n+1)]
    last = [-1 for _ in range(256)]
    dp[0] = 1
    for i in range(1, n+1):
        dp[i] = 2*dp[i-1]
        if last[ord(s[i-1])] != -1:
            dp[i] = dp[i] - dp[last[ord(s[i-1])]]
        last[ord(s[i-1])] = i-1
    return dp[n]

def betterString(str1, str2):
    if distinct_subsequences(str1) >= distinct_subsequences(str2):
        return str1
    else:
        return str2
```

The `distinct_subsequences` function calculates the number of distinct subsequences of a string using dynamic programming. The `betterString` function uses this function to compare the number of distinct subsequences of `str1` and `str2` and returns the better string. The time complexity is O(max(str1.length, str2.length)) and the auxiliary space complexity is also O(max(str1.length, str2.length)).

Knowee AI · Accepted Answer

To solve this problem, we need to create a function that calculates the number of distinct subsequences for each string and then compares them. Here is a Python solution:

```python
def distinct_subsequences(s):
    n = len(s)
    dp = [0 for _ in range(n+1)]
    last = [-1 for _ in range(256)]
    dp[0] = 1
    for i in range(1, n+1):
        dp[i] = 2*dp[i-1]
        if last[ord(s[i-1])] != -1:
            dp[i] = dp[i] - dp[last[ord(s[i-1])]]
        last[ord(s[i-1])] = i-1
    return dp[n]

def betterString(str1, str2):
    if distinct_subsequences(str1) >= distinct_subsequences(str2):
        return str1
    else:
        return str2
```

The `distinct_subsequences` function calculates the number of distinct subsequences of a string using dynamic programming. The `betterString` function uses this function to compare the number of distinct subsequences of `str1` and `str2` and returns the better string. The time complexity is O(max(str1.length, str2.length)) and the auxiliary space complexity is also O(max(str1.length, str2.length)).

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