From the linearlized plot of log (x/m) vs log P in the Freundlich adsorption isotherm, which of the following statements is correct (k and n are constants):a.1/n appears as the interceptb.Both k and 1/n appear in the slopec.Only 1/n appears as the sloped.Log(1/n) appears as the intercept
Question
From the linearlized plot of log (x/m) vs log P in the Freundlich adsorption isotherm, which of the following statements is correct (k and n are constants):a.1/n appears as the interceptb.Both k and 1/n appear in the slopec.Only 1/n appears as the sloped.Log(1/n) appears as the intercept
Solution
The Freundlich adsorption isotherm is represented by the equation:
x/m = kP^(1/n)
Taking the logarithm of both sides, we get:
log(x/m) = log(k) + (1/n)log(P)
This equation is in the form of a straight line equation (y = mx + c), where:
- y = log(x/m)
- x = log(P)
- m (slope) = 1/n
- c (intercept) = log(k)
So, based on this:
a. 1/n does not appear as the intercept, it appears as the slope. b. Both k and 1/n do not appear in the slope. Only 1/n appears in the slope. c. Only 1/n appears as the slope, not the intercept. d. log(1/n) does not appear as the intercept. log(k) appears as the intercept.
Therefore, none of the given statements are correct.
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