What is the maximum possible range of bit-count specifically in n-bit binary counter consisting of ‘n’ number of flip-flops?*0 to 2n0 to 2n + 10 to 2n – 10 to 2n+1/2
Question
What is the maximum possible range of bit-count specifically in n-bit binary counter consisting of ‘n’ number of flip-flops?*0 to 2n0 to 2n + 10 to 2n – 10 to 2n+1/2
Solution
The maximum possible range of bit-count specifically in an n-bit binary counter consisting of ‘n’ number of flip-flops is 0 to 2^n - 1.
Here's why:
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A binary counter is a device that counts up in binary. It's made up of flip-flops, which are simple electronic circuits that can be in one of two states.
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An n-bit binary counter is made up of 'n' flip-flops. Each flip-flop can be in one of two states (0 or 1), so the total number of possible states for the counter is 2^n.
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The range of a counter is the set of possible values it can take. In this case, the counter can take any binary number from 0 to 2^n - 1.
For example, a 2-bit binary counter (made up of 2 flip-flops) can take the values 00, 01, 10, or 11 in binary, which are 0, 1, 2, or 3 in decimal. So the range is 0 to 3, which is 0 to 2^2 - 1.
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