The solubility product (Ksp) of a salt, having general formula MX2, is 4 x 10-12. A salt willdissolve in water to make ions. MX2 will form M2+ and X- in water. The concentration of M2+ions in the aqueous solution of the salt is
Question
The solubility product (Ksp) of a salt, having general formula MX2, is 4 x 10-12. A salt willdissolve in water to make ions. MX2 will form M2+ and X- in water. The concentration of M2+ions in the aqueous solution of the salt is
Solution
The solubility product (Ksp) is given by the equation:
Ksp = [M2+][X-]^2
Given that the salt MX2 dissociates into M2+ and 2X-, the concentration of M2+ ions will be equal to the concentration of MX2 that dissolves. Let's denote this concentration as 's'. Therefore, the concentration of X- ions will be 2s.
Substituting these values into the Ksp equation, we get:
Ksp = s*(2s)^2 = 4s^3
Given that Ksp = 4 x 10^-12, we can solve for s:
4s^3 = 4 x 10^-12 s^3 = 10^-12 s = (10^-12)^(1/3) s = 10^-4 M
Therefore, the concentration of M2+ ions in the aqueous solution of the salt is 10^-4 M.
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