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What will be the output of the following Python code?class A: def __init__(self, x, y): self.x = x self.y = y def __str__(self): return 1 def __eq__(self, other): return self.x * self.y == other.x * other.yobj1 = A(5, 2)obj2 = A(2, 5)print(obj1 == obj2)False1TrueAn exception is thrown

Question

What will be the output of the following Python code?class A: def init(self, x, y): self.x = x self.y = y def str(self): return 1 def eq(self, other): return self.x * self.y == other.x * other.yobj1 = A(5, 2)obj2 = A(2, 5)print(obj1 == obj2)False1TrueAn exception is thrown

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Solution

The output of the given Python code will be True.

Here's the step-by-step explanation:

  1. Two objects obj1 and obj2 of class A are created with the values (5, 2) and (2, 5) respectively.

  2. When we try to print obj1 == obj2, Python calls the __eq__ method of class A to compare these two objects.

  3. In the __eq__ method, it checks whether the product of x and y of obj1 is equal to the product of x and y of obj2. In this case, both are 10, so the method returns True.

  4. Therefore, True is printed as the output.

Note: The __str__ method in the class A is not called in this code, so it doesn't affect the output. If it were called, it would throw a TypeError because it's supposed to return a string, but it returns an integer 1.

This problem has been solved

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