To solve this problem, we need to use the concept of combinations from combinatorics.

Step 1: We need to select 3 boys out of 5. The number of ways to do this is given by the combination formula C(n, r) = n! / [r!(n-r)!], where n is the total number of options, r is the number of options to choose, and '!' denotes factorial.

So, the number of ways to select 3 boys out of 5 is C(5, 3) = 5! / [3!(5-3)!] = 10.

Step 2: We need to select 2 girls out of 4. Using the same combination formula, the number of ways to do this is C(4, 2) = 4! / [2!(4-2)!] = 6.

Step 3: Since these are independent events, we multiply the results together to get the total number of ways to form the committee.

So, the total number of ways to form the committee is 10 * 6 = 60.

Therefore, the answer is (b) 60.

Question

To solve this problem, we need to use the concept of combinations from combinatorics.

Step 1: We need to select 3 boys out of 5. The number of ways to do this is given by the combination formula C(n, r) = n! / [r!(n-r)!], where n is the total number of options, r is the number of options to choose, and '!' denotes factorial.

So, the number of ways to select 3 boys out of 5 is C(5, 3) = 5! / [3!(5-3)!] = 10.

Step 2: We need to select 2 girls out of 4. Using the same combination formula, the number of ways to do this is C(4, 2) = 4! / [2!(4-2)!] = 6.

Step 3: Since these are independent events, we multiply the results together to get the total number of ways to form the committee.

So, the total number of ways to form the committee is 10 * 6 = 60.

Therefore, the answer is (b) 60.

Knowee AI · Accepted Answer

To solve this problem, we need to use the concept of combinations from combinatorics.

Step 1: We need to select 3 boys out of 5. The number of ways to do this is given by the combination formula C(n, r) = n! / [r!(n-r)!], where n is the total number of options, r is the number of options to choose, and '!' denotes factorial.

So, the number of ways to select 3 boys out of 5 is C(5, 3) = 5! / [3!(5-3)!] = 10.

Step 2: We need to select 2 girls out of 4. Using the same combination formula, the number of ways to do this is C(4, 2) = 4! / [2!(4-2)!] = 6.

Step 3: Since these are independent events, we multiply the results together to get the total number of ways to form the committee.

So, the total number of ways to form the committee is 10 * 6 = 60.

Therefore, the answer is (b) 60.

How many ways a committee of 3 boys and 2 girls can be formed from the group of 5 boys and 4 girls?Question 12Answera.21b.60c.14d.48

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