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An ac voltage is applied to a resistance R and an inductor L in series. If R and inductive reactance are both equal to 3 ohm, the phase difference between the applied voltage and the current in the circuit is

Question

An ac voltage is applied to a resistance R and an inductor L in series. If R and inductive reactance are both equal to 3 ohm, the phase difference between the applied voltage and the current in the circuit is

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Solution

The phase difference in an RL circuit (a circuit with a resistor and inductor) can be found using the formula:

tan Φ = XL / R

where:

  • Φ is the phase difference
  • XL is the inductive reactance
  • R is the resistance

Given that both the inductive reactance and resistance are equal (3 ohms), we can substitute these values into the formula:

tan Φ = 3 / 3 = 1

To find the phase difference, we need to find the arctangent (inverse tangent) of 1.

Φ = arctan(1)

This gives us a phase difference of 45 degrees. Therefore, the phase difference between the applied voltage and the current in the circuit is 45 degrees.

This problem has been solved

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