Express 240 as a product of prime factors in index form.
Question
Express 240 as a product of prime factors in index form.
Solution 1
Sure, here are the steps to express 240 as a product of prime factors in index form:
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First, we need to find the prime factors of 240. Prime factors are the prime numbers that divide a number exactly.
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We start by dividing 240 by the smallest prime number, which is 2. 240 divided by 2 is 120.
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We continue this process with the quotient. 120 divided by 2 is 60.
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We divide 60 by 2 and get 30.
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We divide 30 by 2 and get 15.
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Now, 15 cannot be divided by 2, so we move to the next prime number, which is 3. 15 divided by 3 is 5.
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Finally, 5 is a prime number itself, so our process stops here.
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So, the prime factors of 240 are 2, 2, 2, 2, 3, and 5.
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In index form, we write this as 2^4 * 3^1 * 5^1.
So, 240 expressed as a product of prime factors in index form is 2^4 * 3^1 * 5^1.
Solution 2
Sure, here are the steps to express 240 as a product of prime factors in index form:
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First, we need to find the prime factors of 240. We start by dividing 240 by the smallest prime number, which is 2.
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240 ÷ 2 = 120. We can still divide 120 by 2, so we do that next.
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120 ÷ 2 = 60. We can still divide 60 by 2, so we do that next.
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60 ÷ 2 = 30. We can still divide 30 by 2, so we do that next.
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30 ÷ 2 = 15. We can't divide 15 by 2, so we move on to the next prime number, which is 3.
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15 ÷ 3 = 5. We can't divide 5 by 3, so we move on to the next prime number, which is 5.
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5 ÷ 5 = 1. Now we have reached 1, so we stop.
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The prime factors of 240 are therefore 2, 2, 2, 2, 3, and 5.
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In index form, we write this as 2^4 * 3^1 * 5^1.
So, 240 expressed as a product of prime factors in index form is 2^4 * 3^1 * 5^1.
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