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A full-bridge DC-DC converter is fed from DC link voltage of Vdc = 48V as shown in figure. The ratio of transformer winding turns Ns/Np = 6 and converter operates at a switching frequency of 50kHz with duty ratio of 0.5. The peak inverse voltage of the secondary side diode is Answer V.

Question

A full-bridge DC-DC converter is fed from DC link voltage of Vdc = 48V as shown in figure. The ratio of transformer winding turns Ns/Np = 6 and converter operates at a switching frequency of 50kHz with duty ratio of 0.5. The peak inverse voltage of the secondary side diode is Answer V.

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Solution

The peak inverse voltage (PIV) of the secondary side diode in a full-bridge DC-DC converter can be calculated using the formula:

PIV = Vdc * Ns/Np

Given that Vdc = 48V, Ns/Np = 6, we can substitute these values into the formula:

PIV = 48V * 6 = 288V

Therefore, the peak inverse voltage of the secondary side diode is 288V.

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