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When an angle between parallel and perpendicular exists between the applied force and direction of motion, the work done is than the product of force and distance and than zero.

Question

When an angle between parallel and perpendicular exists between the applied force and direction of motion, the work done is than the product of force and distance and than zero.

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Solution

The statement seems to be incomplete, but I'll try to provide an answer based on what I understand.

When the applied force and the direction of motion form an angle, the work done is calculated by the formula:

Work = Force x Distance x cos(θ)

where θ is the angle between the force and the direction of motion.

  1. If the force and the direction of motion are parallel (θ=0), cos(θ) = 1, so the work done is equal to the product of the force and the distance.

  2. If the force and the direction of motion are perpendicular (θ=90), cos(θ) = 0, so the work done is zero.

  3. If the angle is between parallel and perpendicular (0<θ<90), cos(θ) is between 0 and 1. Therefore, the work done is less than the product of the force and the distance, but more than zero.

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Similar Questions

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In case of negative work, the angle between the force and displacement isA 0°  B 45°  C 90° D 180°

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