Solve 𝑥3−6=𝑦3x −6=y for x.A.x = 3y – 18B.𝑥=13𝑦−2x= 31 y−2C.x = 3y + 18D.𝑥=13𝑦+2x= 31 y+2SUBMITarrow_backPREVIOUS
Question
Solve 𝑥3−6=𝑦3x −6=y for x.A.x = 3y – 18B.𝑥=13𝑦−2x= 31 y−2C.x = 3y + 18D.𝑥=13𝑦+2x= 31 y+2SUBMITarrow_backPREVIOUS
Solution
The question seems to be a bit jumbled, but I'll try to solve the equation as best as I can.
The equation is x^3 - 6 = y. To solve for x, we need to isolate x on one side of the equation.
Here are the steps:
- Add 6 to both sides of the equation to isolate x^3 on one side. This gives us x^3 = y + 6.
- To solve for x, we need to take the cube root of both sides. This gives us x = ∛(y + 6).
So, the solution to the equation x^3 - 6 = y for x is x = ∛(y + 6). This doesn't match any of the provided options (A, B, C, D). Please check the question again.
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