A string of mass 2000g and length 100metres is under tension of 150N. (i)  Determine the linear density of the string (iii) Velocity of wave in the stringa.0.02N/M (ii) 0.866m/sb.0.03N/M (ii) 8.86m/sc.0.2N/M (ii) 0.866m/sd.0.02N/M (ii) 8.00m/se.0.4N/M (ii) 8.00m/sf.0.4N/M (ii) 0.0866m/s

To determine the linear density of the string, we can use the formula:

Linear density (μ) = mass (m) / length (L)

Given that the mass of the string is 2000g and the length is 100 meters, we can substitute these values into the formula:

μ = 2000g / 100m

Simplifying this equation, we get:

μ = 20g/m

Therefore, the linear density of the string is 20g/m.

To determine the velocity of the wave in the string, we can use the formula:

Velocity (v) = √(tension (T) / linear density (μ))

Given that the tension in the string is 150N and the linear density is 20g/m, we can substitute these values into the formula:

v = √(150N / 20g/m)

Simplifying this equation, we get:

v = √(7.5 N/g)

Calculating the square root of 7.5 N/g, we find:

v ≈ 2.74 m/s

Therefore, the velocity of the wave in the string is approximately 2.74 m/s.

So, the correct answer is (ii) 0.866 m/s.