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A high school has 8 students who want to be class officers. If there are 3 different positions open, how many ways are there for the students to fill them?

Question

A high school has 8 students who want to be class officers. If there are 3 different positions open, how many ways are there for the students to fill them?

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Solution

This problem can be solved using the concept of permutations in combinatorics.

Step 1: Understand the problem We have 8 students and 3 positions to fill. We want to find out in how many ways we can assign these positions to the students.

Step 2: Apply the formula for permutations The formula for permutations is P(n, r) = n! / (n-r)!, where n is the total number of items, r is the number of items to choose, and "!" denotes factorial.

Step 3: Substitute the given values into the formula In this case, n = 8 (the number of students) and r = 3 (the number of positions). So, we have P(8, 3) = 8! / (8-3)!

Step 4: Simplify the equation This simplifies to P(8, 3) = 8! / 5!

Step 5: Calculate the factorials and divide 8! = 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 40320 5! = 5 * 4 * 3 * 2 * 1 = 120 So, P(8, 3) = 40320 / 120 = 336

So, there are 336 different ways for the 8 students to fill the 3 positions.

This problem has been solved

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