A reaction at 25.0°C evolves 497.mmol of sulfur tetrafluoride gas.Calculate the volume of sulfur tetrafluoride gas that is collected. You can assume the pressure in the room is exactly 1atm. Be sure your answer has the correct number of significant digits
Question
A reaction at 25.0°C evolves 497.mmol of sulfur tetrafluoride gas.Calculate the volume of sulfur tetrafluoride gas that is collected. You can assume the pressure in the room is exactly 1atm. Be sure your answer has the correct number of significant digits
Solution
To solve this problem, we will use the ideal gas law equation, which is PV = nRT.
In this equation:
- P is the pressure, which is given as 1 atm.
- V is the volume, which we are trying to find.
- n is the number of moles, which is given as 497 mmol or 0.497 mol (since 1 mol = 1000 mmol).
- R is the ideal gas constant. Since we are given pressure in atm, we will use the value of R = 0.0821 L·atm/K·mol.
- T is the temperature, which is given as 25.0°C. However, this needs to be converted to Kelvin (the SI unit for temperature) by adding 273.15, which gives us 298.15 K.
Substituting the given values into the equation, we get:
1 atm * V = 0.497 mol * 0.0821 L·atm/K·mol * 298.15 K
Solving for V, we get:
V = (0.497 mol * 0.0821 L·atm/K·mol * 298.15 K) / 1 atm
V = 12.2 L
So, the volume of sulfur tetrafluoride gas that is collected is 12.2 L.
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