Factorize the quadratic expression: 6x2−21x+186x2-21x+18.
Question
Factorize the quadratic expression: 6x2−21x+186x2-21x+18.
Solution
Sure, let's factorize the quadratic expression step by step:
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First, write down the quadratic expression: 6x^2 - 21x + 18
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The quadratic expression is in the form ax^2 + bx + c. In this case, a = 6, b = -21, and c = 18.
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We need to find two numbers that multiply to give ac (which is 6*18 = 108) and add up to give b (which is -21).
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The two numbers that satisfy these conditions are -9 and -12 (because -9*-12 = 108 and -9 + -12 = -21).
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Rewrite the middle term of the quadratic expression as the sum of the terms -9x and -12x: 6x^2 - 9x - 12x + 18
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Factor by grouping: 3x(2x - 3) - 6(2x - 3)
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Notice that the terms in the parentheses are the same, so we can factor them out: (2x - 3)(3x - 6)
So, the factorized form of the quadratic expression 6x^2 - 21x + 18 is (2x - 3)(3x - 6).
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