elect the correct answerA person covers a certain distance with certain speed if he increases his speed by 15 km/hr. Then he will be 16 min. early. By how much time he will be late if he reduces his speed by 12 km/hr, if his initial speed is 60 km/hr?Options15 min25 min20 min24 min

To solve this problem, we need to understand the relationship between speed, distance, and time. The formula is Distance = Speed x Time.

1. First, let's find the distance. We know that if the person increases his speed by 15 km/hr, he will be 16 minutes early. So, the distance covered is (60 km/hr + 15 km/hr) x (time - 16/60 hours) = 75 km/hr x (time - 4/15 hours).

2. We also know that the same distance is covered at the initial speed of 60 km/hr in the original time. So, we can set up the equation 60 km/hr x time = 75 km/hr x (time - 4/15 hours).

3. Solving this equation for time, we get time = 1 hour.

4. Now, if the person reduces his speed by 12 km/hr, the new speed is 60 km/hr - 12 km/hr = 48 km/hr.

5. To find out how much time he will take to cover the same distance at this reduced speed, we use the formula Time = Distance / Speed = (60 km/hr x 1 hour) / 48 km/hr = 1.25 hours.

6. To find out how much later this is than the original time, we subtract the original time from this new time: 1.25 hours - 1 hour = 0.25 hours.

7. Convert this time to minutes by multiplying by 60: 0.25 hours x 60 = 15 minutes.

So, if the person reduces his speed by 12 km/hr, he will be 15 minutes late. The correct answer is 15 min.