In a {93/41}Nb nucleus, the number of protons, neutrons, and electrons is

In a {93/41}Nb nucleus, the number of protons is 41. This is because the atomic number, which is the number at the bottom, represents the number of protons in an atom.

The number of neutrons can be found by subtracting the atomic number from the mass number (the number at the top). So, 93 - 41 = 52. Therefore, there are 52 neutrons in a {93/41}Nb nucleus.

The number of electrons in a neutral atom is equal to the number of protons. Therefore, a {93/41}Nb atom has 41 electrons. However, please note that the number of electrons can change if the atom is ionized (if it gains or loses electrons), but the question does not specify this, so we assume the atom is neutral.