A swiming pool can be filled with water by two pipes in 12 hours. If a larger pipe takes less than the smaller pipe to fill the pool, find the time each pipe will take individually.
Question
A swiming pool can be filled with water by two pipes in 12 hours. If a larger pipe takes less than the smaller pipe to fill the pool, find the time each pipe will take individually.
Solution
This problem can be solved using the concept of work and time.
Let's denote:
- the time it takes for the larger pipe to fill the pool as L hours
- the time it takes for the smaller pipe to fill the pool as S hours
From the problem, we know that the larger pipe works faster than the smaller one, so L < S.
We also know that when the two pipes work together, they can fill the pool in 12 hours. This means that in one hour, they can fill 1/12 of the pool.
So, we can write the equation:
1/L + 1/S = 1/12
We also know that L < S.
Unfortunately, with only one equation and two unknowns, we can't find a unique solution. We need more information to solve this problem.
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