The concentration of OH⁻ ions in a bottle of ammonium hydroxide is 39 x 10⁻⁷ M right after the cork is removed. What is its pH value?Select one:a.6.3b.2.9c.5.4d.8.6
Question
The concentration of OH⁻ ions in a bottle of ammonium hydroxide is 39 x 10⁻⁷ M right after the cork is removed. What is its pH value?Select one:a.6.3b.2.9c.5.4d.8.6
Solution
To solve this problem, we need to use the formula for pOH and pH.
First, we need to find the pOH. The pOH is the negative logarithm (base 10) of the concentration of OH⁻ ions.
Given that the concentration of OH⁻ ions is 39 x 10⁻⁷ M, we can calculate the pOH as follows:
pOH = -log[OH⁻] pOH = -log(39 x 10⁻⁷) pOH = -(-6.41) pOH = 6.41
Next, we need to find the pH. The pH and pOH of a solution at 25°C are related by the following equation:
pH + pOH = 14
So, we can calculate the pH as follows:
pH = 14 - pOH pH = 14 - 6.41 pH = 7.59
However, this value is not among the options given. It's possible there may be a mistake in the problem or the given options.
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