Select the correct answerOutput by the below given code is:#include<stdio.h>int Function(int x, int *P1, int **P2) {  int y, z;  **P2 += 2;   z = **P2;  *P1 += 3;   y = *P1;   x += 4;   return x + y + z; }   int main() {   int c, *b, **a;   c = 10;   b = &c;   a = &b;   printf("%d ", Function(c, b, a));   return 0;}Options40414344

The correct answer is 44.

Here's the step-by-step explanation:

1. The initial value of c is 10. b is a pointer to c, and a is a pointer to the pointer b.

2. The function Function is called with c, b, and a as arguments. Inside the function, x is c (10), P1 is b (&c), and P2 is a (&b).

3. **P2 += 2; This line adds 2 to the value pointed by P2 (which is c). So, c becomes 12.

4. z = **P2; Now, z is assigned the value of c which is 12.

5. *P1 += 3; This line adds 3 to the value pointed by P1 (which is c). So, c becomes 15.

6. y = *P1; Now, y is assigned the value of c which is 15.

7. x += 4; This line adds 4 to x. So, x becomes 14.

8. return x + y + z; This line returns the sum of x, y, and z which is 14 + 15 + 15 = 44.

So, the output of the program is 44.