Let's denote the two natural numbers as x and y.

From the problem, we know that:

1) x + y = 12
2) xy = 35

We are asked to find the sum of the reciprocals of the two numbers, which is 1/x + 1/y.

We can rewrite 1/x + 1/y as (x + y) / (xy).

Substituting the given values from the problem into this equation, we get:

(12) / (35) = 0.34285714285714286

So, the sum of the reciprocals of the two numbers is approximately 0.343.

Question

Let's denote the two natural numbers as x and y.

From the problem, we know that:

1) x + y = 12
2) xy = 35

We are asked to find the sum of the reciprocals of the two numbers, which is 1/x + 1/y.

We can rewrite 1/x + 1/y as (x + y) / (xy).

Substituting the given values from the problem into this equation, we get:

(12) / (35) = 0.34285714285714286

So, the sum of the reciprocals of the two numbers is approximately 0.343.

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