An object initially at rest falls freely near Earth's surface. How long does it take the object to attain a speed of 98 m/s?A 0.1 sB 10 sC 98 sD 960 s
Question
An object initially at rest falls freely near Earth's surface. How long does it take the object to attain a speed of 98 m/s?A 0.1 sB 10 sC 98 sD 960 s
Solution
The acceleration due to gravity near Earth's surface is approximately 9.8 m/s². This means that an object falling freely (ignoring air resistance) will increase its speed by 9.8 m/s every second.
To find out how long it takes for the object to reach a speed of 98 m/s, we can use the formula:
v = gt
where: v is the final velocity (98 m/s in this case), g is the acceleration due to gravity (9.8 m/s²), and t is the time it takes to reach that velocity.
Rearranging the formula to solve for t gives us:
t = v/g
Substituting the given values into the formula gives us:
t = 98 m/s / 9.8 m/s² = 10 s
So, it takes 10 seconds for the object to reach a speed of 98 m/s. The correct answer is B, 10 s.
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