Find the inverse of the function.(a) p(x) = 7 + (2x + 1)3(b) k(x) = 7√15x + 2(c) g (x) = 2x + 146x + 1
Question
Find the inverse of the function.(a) p(x) = 7 + (2x + 1)3(b) k(x) = 7√15x + 2(c) g (x) = 2x + 146x + 1
Solution
Sure, let's find the inverse of each function step by step:
(a) p(x) = 7 + (2x + 1)³
Step 1: Replace p(x) with y: y = 7 + (2x + 1)³ Step 2: Swap x and y: x = 7 + (2y + 1)³ Step 3: Solve for y: Subtract 7 from both sides: x - 7 = (2y + 1)³ Take the cube root of both sides: ∛(x - 7) = 2y + 1 Subtract 1 and divide by 2: y = 0.5(∛(x - 7) - 1) So, the inverse of p(x) is p^-1(x) = 0.5(∛(x - 7) - 1)
(b) k(x) = 7√(15x) + 2
Step 1: Replace k(x) with y: y = 7√(15x) + 2 Step 2: Swap x and y: x = 7√(15y) + 2 Step 3: Solve for y: Subtract 2 from both sides: x - 2 = 7√(15y) Divide by 7: (x - 2)/7 = √(15y) Square both sides: ((x - 2)/7)² = 15y Divide by 15: y = ((x - 2)/7)² / 15 So, the inverse of k(x) is k^-1(x) = ((x - 2)/7)² / 15
(c) g(x) = 2x + 146x + 1
This function seems to be incorrect as it is not clear whether it is a quadratic or linear function. Please provide the correct function.
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