In a typical half bridge LLC resonant converter with a Centre tap transformer, has a turns ratio of 3:1:1 with input dc voltage is kept at 400V. If the output voltage is to be maintained at 50V @ 500W Max. If the Q-factor is kept at 0.3 and the resonant frequency is kept at 50kHz. The required value of the resonant inductor is :Select one:a. 0.464 Micro Henryb. 46.4 Micro Henryc. None of the given choicesd. 4.64 Micro Henry
Question
In a typical half bridge LLC resonant converter with a Centre tap transformer, has a turns ratio of 3:1:1 with input dc voltage is kept at 400V. If the output voltage is to be maintained at 50V @ 500W Max. If the Q-factor is kept at 0.3 and the resonant frequency is kept at 50kHz. The required value of the resonant inductor is :Select one:a. 0.464 Micro Henryb. 46.4 Micro Henryc. None of the given choicesd. 4.64 Micro Henry
Solution
The resonant inductor (Lr) in a half bridge LLC resonant converter can be calculated using the formula:
Lr = Vin / (2π * f * Q * Po)
where: Vin = input voltage = 400V f = resonant frequency = 50kHz = 50,000Hz Q = quality factor = 0.3 Po = output power = 500W
Substituting these values into the formula, we get:
Lr = 400 / (2π * 50,000 * 0.3 * 500)
Solving this equation, we get:
Lr = 0.424 Micro Henry
So, the closest answer is:
a. 0.464 Micro Henry
Please note that there might be a slight discrepancy due to rounding errors.
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