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Oil leaked from a tank at a rate of r(t) liters per hour. The rate decreased as time passed, and values of the rate at two hour time intervals are shown in the table. Find lower and upper estimates for the total amount of oil that leaked out.V ≈ L (lower estimate)V ≈ L (upper estimate)t (h) 0 2 4 6 8 10r(t) (L/h) 8.7 7.9 6.7 6.2 5.7 5.1

Question

Oil leaked from a tank at a rate of r(t) liters per hour. The rate decreased as time passed, and values of the rate at two hour time intervals are shown in the table. Find lower and upper estimates for the total amount of oil that leaked out.V ≈ L (lower estimate)V ≈ L (upper estimate)t (h) 0 2 4 6 8 10r(t) (L/h) 8.7 7.9 6.7 6.2 5.7 5.1

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Solution

The given table represents the rate of oil leakage at different time intervals. To find the lower and upper estimates for the total amount of oil leaked, we can use the concept of Riemann sums in calculus, specifically the Left Hand Rule (LHR) and Right Hand Rule (RHR).

The Left Hand Rule (LHR) uses the left endpoint of each interval to estimate the total. This will give us the lower estimate.

The Right Hand Rule (RHR) uses the right endpoint of each interval to estimate the total. This will give us the upper estimate.

The width of each interval is 2 hours.

Lower estimate (LHR): = (8.7 * 2) + (7.9 * 2) + (6.7 * 2) + (6.2 * 2) + (5.7 * 2) = 34.8 liters

Upper estimate (RHR): = (7.9 * 2) + (6.7 * 2) + (6.2 * 2) + (5.7 * 2) + (5.1 * 2) = 31.6 liters

So, the lower estimate for the total amount of oil that leaked out is approximately 34.8 liters and the upper estimate is approximately 31.6 liters.

This problem has been solved

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