The problem you're asking about is a Poisson distribution problem. The Poisson distribution gives the probability of a given number of events (in this case, car sales) happening in a fixed interval of time or space (a day) when these events occur with a known average rate (2.5 car sales per day) and independently of the time since the last event.

The formula for the Poisson distribution is:

P(k events in interval) = λ^k * e^-λ / k!

where:
- λ is the average rate of value (in this case, 2.5 car sales per day)
- k is the actual number of events (in this case, 5 car sales)
- e is the base of the natural logarithm (approximately equal to 2.71828)
- k! is the factorial of k

Substituting the given values into the formula, we get:

P(5 car sales in a day) = 2.5^5 * e^-2.5 / 5!

Calculating this will give us the probability that on a randomly selected day, the car distributor will sell 5 cars.

Question

The problem you're asking about is a Poisson distribution problem. The Poisson distribution gives the probability of a given number of events (in this case, car sales) happening in a fixed interval of time or space (a day) when these events occur with a known average rate (2.5 car sales per day) and independently of the time since the last event.

The formula for the Poisson distribution is:

P(k events in interval) = λ^k * e^-λ / k!

where:
- λ is the average rate of value (in this case, 2.5 car sales per day)
- k is the actual number of events (in this case, 5 car sales)
- e is the base of the natural logarithm (approximately equal to 2.71828)
- k! is the factorial of k

Substituting the given values into the formula, we get:

P(5 car sales in a day) = 2.5^5 * e^-2.5 / 5!

Calculating this will give us the probability that on a randomly selected day, the car distributor will sell 5 cars.

Knowee AI · Accepted Answer

The problem you're asking about is a Poisson distribution problem. The Poisson distribution gives the probability of a given number of events (in this case, car sales) happening in a fixed interval of time or space (a day) when these events occur with a known average rate (2.5 car sales per day) and independently of the time since the last event.

The formula for the Poisson distribution is:

P(k events in interval) = λ^k * e^-λ / k!

where:
- λ is the average rate of value (in this case, 2.5 car sales per day)
- k is the actual number of events (in this case, 5 car sales)
- e is the base of the natural logarithm (approximately equal to 2.71828)
- k! is the factorial of k

Substituting the given values into the formula, we get:

P(5 car sales in a day) = 2.5^5 * e^-2.5 / 5!

Calculating this will give us the probability that on a randomly selected day, the car distributor will sell 5 cars.

A car distributor in City Y experiences an average of 2.5 car sales daily. Find the probability that on a randomly selected day, they will sell 5 car: 0.0668 0.544 0.082 0.205

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