John pulls a 50 kg crate with a force of 215 N to the right. There is a frictional force of 200 N acting to the left, between the crate and the ground. Alan assists John by pushing the crate with a force of 300 N also to the right.What is the acceleration of the trolley in m/s2?Group of answer choices14.3 to the right5.7 to the right15 750 to the right6.3 to the right
Question
John pulls a 50 kg crate with a force of 215 N to the right. There is a frictional force of 200 N acting to the left, between the crate and the ground. Alan assists John by pushing the crate with a force of 300 N also to the right.What is the acceleration of the trolley in m/s2?Group of answer choices14.3 to the right5.7 to the right15 750 to the right6.3 to the right
Solution
To solve this problem, we first need to find the net force acting on the crate.
The net force is the sum of all forces acting on an object. In this case, we have two forces acting to the right (John's force and Alan's force) and one force acting to the left (the frictional force).
The net force (F_net) can be calculated as follows:
F_net = (Force by John + Force by Alan) - Frictional force F_net = (215 N + 300 N) - 200 N F_net = 515 N - 200 N F_net = 315 N
The net force acting on the crate is 315 N to the right.
Next, we use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The formula is:
Acceleration (a) = F_net / mass
Substituting the given values into the formula, we get:
a = 315 N / 50 kg a = 6.3 m/s²
So, the acceleration of the crate is 6.3 m/s² to the right.
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