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Neutrons traveling at 0.575 m/s are directed through a pair of slits separated by 1.00 mm. A detector screen is placed 10.6 m from the slits.What is the de Broglie wavelength of the neutrons? Use units of metres

Question

Neutrons traveling at 0.575 m/s are directed through a pair of slits separated by 1.00 mm. A detector screen is placed 10.6 m from the slits.What is the de Broglie wavelength of the neutrons? Use units of metres

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Solution

To find the de Broglie wavelength of the neutrons, we can use the de Broglie equation:

λ = h / p

where: λ is the de Broglie wavelength, h is the Planck constant (6.62607015 × 10^-34 m^2 kg / s), p is the momentum of the particle.

The momentum of a particle is given by the product of its mass and velocity, so:

p = m * v

where: m is the mass of the neutron (1.674927471 × 10^-27 kg), v is the velocity of the neutron (0.575 m/s).

Substituting the values for m and v into the equation for p, we get:

p = (1.674927471 × 10^-27 kg) * (0.575 m/s) = 9.63083420675 × 10^-28 kg m/s

Then, substituting the value for p into the de Broglie equation, we get:

λ = (6.62607015 × 10^-34 m^2 kg / s) / (9.63083420675 × 10^-28 kg m/s) = 6.877 × 10^-10 m

So, the de Broglie wavelength of the neutrons is approximately 6.877 × 10^-10 metres.

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