What least number must be added to 1056, so that the sum is completely divisible by 23 ?
Question
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
Solution
To find the least number that must be added to 1056 so that the sum is completely divisible by 23, you need to follow these steps:
- Divide 1056 by 23.
- Find the remainder of this division.
- Subtract the remainder from 23.
Let's do the math:
- 1056 ÷ 23 = 45 remainder 21
- The remainder is 21.
- 23 - 21 = 2
So, the least number that must be added to 1056 to make it divisible by 23 is 2.
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