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Don (82.8 kg) is going bungee jumping. The bridge he will jump off of is 54.0 m above the ground. After Don jumps, he comes to a spot 10.3 m above the ground before the bungee pulls him back.How much elastic energy is in the bungee cord when Don is 10.3 meters above the ground?

Question

Don (82.8 kg) is going bungee jumping. The bridge he will jump off of is 54.0 m above the ground. After Don jumps, he comes to a spot 10.3 m above the ground before the bungee pulls him back.How much elastic energy is in the bungee cord when Don is 10.3 meters above the ground?

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Solution

To solve this problem, we need to use the principle of conservation of energy. This principle states that the total energy in a closed system remains constant. In this case, the total energy is the sum of the gravitational potential energy and the elastic potential energy in the bungee cord.

  1. First, we calculate the gravitational potential energy (PE) at the highest point (the bridge), which is given by the formula PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.

    PE = (82.8 kg) * (9.8 m/s^2) * (54.0 m) = 43681.44 Joules

  2. Then, we calculate the gravitational potential energy at the lowest point (10.3 m above the ground), using the same formula:

    PE = (82.8 kg) * (9.8 m/s^2) * (10.3 m) = 8333.04 Joules

  3. The difference between these two energies is the elastic potential energy stored in the bungee cord when Don is 10.3 meters above the ground.

    Elastic energy = PE at highest point - PE at lowest point Elastic energy = 43681.44 Joules - 8333.04 Joules = 35348.4 Joules

So, the elastic energy in the bungee cord when Don is 10.3 meters above the ground is 35348.4 Joules.

This problem has been solved

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