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Jamieson is competing in his school’s 3.0-metre diving competition. For his last dive, he is performing a forward somersault. The duration of the dive must be exactly 1.75 seconds or he will under- or over-rotate before hitting the water. He jumps upwards off the board with a vertical velocity of 6.0 m s−1 and takes $t$t​ seconds to land in the pool. Take the upwards direction as positive.Which of the following constant acceleration equations could correctly calculate the velocity of the diver as they hit the water?A$v=u+at$v=u+at​B$s=ut+\frac{1}{2}at^2$s=ut+12​at2​C$s=vt-\frac{1}{2}at^2$s=vt−12​at2​D$v^2=u^2+2as$v2=u2+2as​

Question

Jamieson is competing in his school’s 3.0-metre diving competition. For his last dive, he is performing a forward somersault. The duration of the dive must be exactly 1.75 seconds or he will under- or over-rotate before hitting the water. He jumps upwards off the board with a vertical velocity of 6.0 m s−1 and takes ttt​ seconds to land in the pool. Take the upwards direction as positive.Which of the following constant acceleration equations could correctly calculate the velocity of the diver as they hit the water?Av=u+atv=u+atv=u+at​Bs=ut+12at2s=ut+\frac{1}{2}at^2s=ut+12​at2​Cs=vt12at2s=vt-\frac{1}{2}at^2s=vt−12​at2​Dv2=u2+2asv^2=u^2+2asv2=u2+2as​

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Solution

The correct equation to calculate the velocity of the diver as they hit the water is Av=u+atv=u+at. This equation is derived from the basic principles of motion. Here, v is the final velocity, u is the initial velocity, a is the acceleration (which would be due to gravity in this case), and t is the time. This equation is used when the acceleration is constant, as it is in this case (the acceleration due to gravity is a constant). The other equations are also equations of motion, but they are used to calculate different parameters of motion.

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