What will be the pH and % α (degree of hydrolysis) respectively for the salt BA of 0.1 M concentration?(Given : Ka for HA = 10–6 and Kb for BOH = 10–6)5, 1%7, 10%9, 0.01%7, 0.01%

The question seems to be incomplete. However, I can guide you on how to calculate the pH and degree of hydrolysis for a salt BA given the Ka for HA and Kb for BOH.

Step 1: Calculate the ionization constant of water (Kw) which is typically 1.0 x 10^-14 at 25 degrees Celsius.

Step 2: Use the given Ka for HA and Kb for BOH to calculate the K for the salt BA. The relationship is Ka x Kb = Kw. So, K for BA would be Kw/Ka or Kw/Kb.

Step 3: Use the formula for calculating the degree of hydrolysis (h) which is sqrt(K/C), where K is the ionization constant for the salt BA and C is the concentration of the salt.

Step 4: Convert the degree of hydrolysis to a percentage by multiplying by 100.

Step 5: Calculate the pH of the solution using the formula pH = 7 + 1/2 * log(h) if the salt is of a weak acid and strong base, or pH = 7 - 1/2 * log(h) if the salt is of a strong acid and weak base.

Please note that the above steps are a general guide and the actual calculations may vary depending on the specific values given in the problem.